# Ways to return function values in C

March 25, 2022 5 min

I was having a chit-chat with a friend discussing some C language shenanigans when he sent me a code snippet, he wanted me fix the code and get it to work in 4 different ways.

#include <stdio.h>

void calc (int x, int y);
int main(void){
int x = 10, y = 50;
printf("sum=%d ", sum);
printf("mult=%d", mul);
}

void calc (int x, int y){
int sum = x + y;
int mul = x * y;
}


There are two main takeaways from the above snippet:

• The calc function is never called in main.
• Even if we called it in main, the sum and mul variables are locals to the scope of calc.

The obvious solution to me was to just make these variables globals then we can just call calc in main and we're done, but he wanted me to do it in 4 different ways, that was clearly an exercise of passing values around in C.

## Using Global Variables

#include <stdio.h>

int sum, mul;
void calc (int x, int y);

int main(void){
int x = 10, y = 50;
calc(x, y);
printf("sum=%d ", sum);
printf("mult=%d", mul);
}

void calc (int x, int y){
sum = x + y;
mul = x * y;
}


Output

sum=60 mult=500

This is pretty simple, by making the sum and mul variables global, we just expand their scope to the whole program.

## Using Pointers

#include <stdio.h>

void calc (int x, int y, int *sum, int *mul);

int main(void){
int x = 10, y = 50;
int sum, mul;
calc(x, y, &sum , &mul);
printf("sum=%d ", sum);
printf("mult=%d", mul);
}

void calc (int x, int y, int *sum, int *mul){
*sum = x + y;
*mul = x * y;
}


In this solution we declared these variables in the main function and passed them by pointers (i.e. we passed a reference to their location in memory), by doing this we can freely modify a variable from another scope since we directly access the variable's location in memorey.

i.e. we dereference a memory address and modify the value that the address is pointing to.

### Bonus: Passing by Reference (C++)

#include <stdio.h>

void calc (int x, int y, int &sum, int &mul);

int main(void){
int x = 10, y = 50;
int sum, mul;
calc(x, y, sum , mul);
printf("sum=%d ", sum);
printf("mult=%d", mul);

return 0;
}

void calc (int x, int y, int &sum, int &mul){
sum = x + y;
mul = x * y;
}


C++ allows us to directly pass the address of sum and mul without using pointers, we just pass them by reference.

That's why I think people should be careful of using the terms "pass-by-pointer" and "pass-by-reference" interchangeably as these are two different things.

## Using Arrays

#include <stdio.h>

int calc (int x, int y, int *result);

int main(void){
int x = 10, y = 50;
int result;
calc(x, y, result);
printf("sum=%d ", result);
printf("mult=%d", result);
}

int calc (int x, int y, int *result){
int sum = x + y;
int mul = x * y;
result = sum;
result = mul;
}


Passing values with arrays are useful when our values have the same type, It is very similar to passing by pointer/reference since we actually pass the address of the array to the calc function, It's values is then modified using the array notation my_array[index] = value which is really equivalent to *(my_array + index) = value.

## Using Structs

#include <stdio.h>

struct Result{
int sum, mul;
};

struct Result calc (int x, int y);

void main(void){
int x = 10, y = 50;
struct Result result = calc(x, y);
printf("sum=%d", result.sum);
printf("mult=%d", result.mul);
}

struct Result calc (int x, int y){
struct Result res;
res.sum = x + y;
res.mul = x * y;
return res;
}


C structs are a decent way of passing multiple values around functions, especially when these values are of different types, we can also get around typing Struct Result a bunch of times by adding a typedef that introduces a new type in our code, It makes our code a bit cleaner and easier to read.

This is the same code but with introducing the typedef.

#include <stdio.h>

typedef struct Result{
int sum, mul;
};

Result calc (int x, int y);

int main(void){
int x = 10, y = 50;
Result result = calc(x, y);
printf("sum=%d ", result.sum);
printf("mult=%d", result.mul);
}

Result calc (int x, int y){
Result res;
res.sum = x + y;
res.mul = x * y;
return res;
}


Note: All these solutions are ways to return multiple values from a function, unlike modern languages like python we can't do this in C, another good solution is splitting the calc function two two spearate functions where each one of them will return It's result, sometimes this can be better than the above approaches and It's all depending on taste.

#include <stdio.h>

int sum (int x, int y);
int mul (int x, int y);

void main(void){
int x = 10, y = 50;
printf("sum=%d ", sum(x,y));
printf("mult=%d", mul(x,y));
}

int sum (int x, int y){
int sum = x + y;
return sum;
}

int mul (int x, int y){
int mul = x * y;
return mul;
}